Well you don't have an curly braces anywhere in your code..
Try this:
<?php
If (($_POST['fname']=="") || ($_POST['lname']=="") {
echo("Please Enter Information In All The Fields !!!"); }
Else {
$connectionString=odbc_connect("PHPInsert","sa","");
$query="INSERT INTO PHPUsers(FName,LName) VALUES
($_POST['fname'],$_POST['lname'])";
$exeQuery=odbc_do($connectionString,$query);
odbc_close($connectionString);
echo("Hi ",$_POST['fname']," ",$_POST['lname'],"Thank You For
Registering !!!");
}
?>
Rick
"It is the mark of an educated mind to be able to entertain a thought
without accepting it." - Aristotle
> From: "Arpan De" <[EMAIL PROTECTED]>
> Date: Tue, 30 Apr 2002 02:34:53 +0530
> To: [EMAIL PROTECTED]
> Subject: [PHP] Insert in database
>
> I have a simple HTML Form where a user has to enter his first & last name
> which will be inserted in a SQL Server database table. The PHP code which
> does the needful is as follows (I have created a DSN named PHPInsert
> successfully as well):
>
> <?php
> If(($_POST['fname']=="") || ($_POST['lname']=="")
> echo("Please Enter Information In All The Fields !!!");
> Else
> $connectionString=odbc_connect("PHPInsert","sa","");
> $query="INSERT INTO PHPUsers(FName,LName) VALUES
> ($_POST['fname'],$_POST['lname'])";
> $exeQuery=odbc_do($connectionString,$query);
> odbc_close($connectionString);
>
> echo("Hi ",$_POST['fname']," ",$_POST['lname'],"Thank You For
> Registering !!!");
> ?>
>
> The above code, when executed, throws the following error:
>
> Parse error: parse error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting
> T_STRING or T_VARIABLE or T_NUM_STRING
>
> pointing to the line where the variable $query is assigned the SQL
> statement. What does the above error mean? Both the fields in the database
> are varchar datatype. The table also has an ID field which is an IDENTITY
> field auto-incrementing by 1. Where am I going wrong?
>
> Thanks,
>
> Arpan
>
>
>
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