It means your query failed. www.php.net/mysql_error
---John Holmes... > -----Original Message----- > From: Dan McCullough [mailto:[EMAIL PROTECTED]] > Sent: Sunday, April 28, 2002 3:15 PM > To: [EMAIL PROTECTED] > Subject: [PHP] Supplied argument is not a valid MySQL result resource > > What does that error mean? > > $result = mysql_query('select * from aannh_towns;'); > echo 'info stored'; > while ($query_data = mysql_fetch_array($result)) { > echo "", $query_data['town'], "", $query_data['town_id'], ""; } > ?> > > ===== > dan mccullough > -------------------------------------------------------- > "Theres no such thing as a problem unless the servers are on fire!" > > > __________________________________________________ > Do You Yahoo!? > Yahoo! Health - your guide to health and wellness > http://health.yahoo.com > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
