Erik Price wrote: > > On Wednesday, April 17, 2002, at 03:59 PM, Robert Cummings wrote: > > > Now if what you meant was the following: > > > > $objectFoo = new MyObject(); > > $objectFee = &$objectFoo; > > > > unset( $objectFoo ); > > > > Then the object shouldn't be deleted since $objectFee is still > > referencing > > it. You will just break the reference. Correct me if I'm wrong *chuckle* > > What if I did > > $objectFoo = new MyObject; > $objectFee = $objectFoo; > > unset($objectFoo); > > essentially, does PHP make a (deep|shallow) copy of an object in this > reassignment, or is it just creating a new reference?
Should be a copy, and it should be safe... though I recall a discussion last week that displayed an interesting bug (feature?). Cheers, Rob. -- .-----------------. | Robert Cummings | :-----------------`----------------------------. | Webdeployer - Chief PHP and Java Programmer | :----------------------------------------------: | Mail : mailto:[EMAIL PROTECTED] | | Phone : (613) 731-4046 x.109 | :----------------------------------------------: | Website : http://www.webmotion.com | | Fax : (613) 260-9545 | `----------------------------------------------' -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
