He wants the third sunday in february which can't be handled by
your code :) since the third sunday could fall on any number of
days. The following isn't very optimal but will work (not syntax
checked either).
$i = 1;
while( $i++ <= 7 )
{
//
// First we find the first Sunday in February.
//
if( date( '%a', mktime( 0,0,0, 2,$i,2002 ) == 'Sun' )
{
break;
}
}
return date( '%s-%m-%Y', mktime( 0,0,0, 2,($i + 14),2002 );
Generalization of the above is left to you as an exercise *grin*.
Cheers,
Rob.
-----------------------------------------------------------------
Tyler Longren wrote:
>
> <?
> $month = date("m");
> $day = date("d");
> if ($month == "10" && $day == "31") {
> print "It's Halloween!";
> }
> ?>
>
> you could do something similar to that.
>
> tyler
>
> ----- Original Message -----
> From: "Tom Beidler" <[EMAIL PROTECTED]>
> To: "php list" <[EMAIL PROTECTED]>
> Sent: Monday, April 15, 2002 2:17 PM
> Subject: [PHP] calculating US holidays
>
> > I need to calculate the date to see if it's a holiday, i.e. is today
> > presidents day, which happens to be the third monday of february. Can
> > someone point me to some code that can do that?
> >
> >
> > --
> > PHP General Mailing List (http://www.php.net/)
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> >
> >
>
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| Webdeployer - Chief PHP and Java Programmer |
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