Turn error_reporting to:
error_reporting (E_ERROR | E_WARNING | E_PARSE);
// that is the function to mess in the code, you can also set it within
php.ini
then fix your function:
It cannot have more then one return (sure it can, but will break the
execution on the first-come basis).
If you need them all three then make yourself an array and return it:
Function return_array() {
....
Return Array('date'=>$date, 'time'=>$time, 'year'=>$year);
}
or, make those three variables global;
Function return_array() {
Global $realday, $month, $year; // add this line and your
function will work
....
Return True; // is enough
}
Sincerely,
Maxim Maletsky
Founder, Chief Developer
PHPBeginner.com (Where PHP Begins)
[EMAIL PROTECTED]
www.phpbeginner.com
> -----Original Message-----
> From: Simonk [mailto:[EMAIL PROTECTED]]
> Sent: Thursday, April 04, 2002 5:39 PM
> To: [EMAIL PROTECTED]
> Subject: [PHP] Help with " Function " parameter
>
> I have programed a function for counting Date:
>
> function Datereturn()
> {
> $monthorder = Array ( 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30,
31);
> $day = Date("j");
> $monthday = Date("t");
> $month = Date("n");
> $year = Date("Y");
> $current = 42 - ($monthday - $day);
> if ($current > $monthorder[$month])
> { $realday = $current - $monthorder[$month];
> $month = $month + 2;
> if ($month > 12)
> { $year = $year + 1;
> $month = $month - 12; }
> }
> else
> { $realday = $current;
> $month = $month + 1;
> if ($month > 12)
> { $year = $year + 1;
> $month = $month - 12; } }
> Return $realday;
> Return $month;
> Return $year;
> }
>
>
> But when I want to echo out the result, I have typed:
>
> Datereturn();
> echo "$year, $month, $realday";
>
> Then the server return:
> Undefined variable year, month, realday
>
> plz help!
>
>
>
>
>
>
>
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