No it's right. Because $count will equal 10 and it'll print it out, the test will fail and then it'll trace the recursion back and print the j's. It would be a bug if it printed an 11, but it's right the way it is. Dave
"Uros Gruber" <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > Hi! > > This is a code > > function Test() > { > static $count = 0; > > $count++; > echo $count; > if ($count < 10) { > Test (); > } > echo "j"; > } > test(); > > Output is > > 12345678910jjjjjjjjjj > > Why is there 10 j at the and. If this would work it can be > only one. If $count is grater than 10 it does not call itself > but end. Is this maybe a bug or what. > > > -- > lp, > Uros mailto:[EMAIL PROTECTED] > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
