|
Hy,
When I try to see my page I have this message and I
don't know why.
If someone can explain to me.
Thank You
Parse error: parse error, expecting `')'' in
liensfr.php on line 17
Source code :
<html>
<head> <LINK REL="stylesheet" HREF="mmenu.css"> <SCRIPT LANGUAGE="javascript" src="javascript:void(0);"></SCRIPT> <title>Liens</title> </head> <body
>
<SCRIPT LANGUAGE="javascript" src="javascript:void(0);"></SCRIPT> <br><br><br><br> <table align="center" cellspacing="0" cellpadding="0" border="0" width="80%"> <?php $db = mysql_connect(database); $sql= "SELECT * FROM liens"; $res = mysql_query($sql, $db); $nbline = mysql_num_rows($res); For ($i = 1; $i < ($nbline+1); i++) { // Line 17 print "<tr>"; print "<td>"; $req = "SELECT nom FROM liens WHERE auto = $i"; $result = mysql_query($req, $db); print "<center>"; echo "$result"; print "<br>"; $req = "SELECT adresse FROM liens WHERE auto = $i"; $result = mysql_query($req, $db); print "<a href='".$result."'>"; echo "$result"; print "<br>"; $req = "SELECT banniere FROM liens WHERE auto = $i"; $result = mysql_query($req, $db); If ($result != "") { print "<img scr='".$result."' width='300' height='150'></a><br>"; } $req = "SELECT comment FROM liens WHERE auto = $i"; $result = mysql_query($req, $db); echo "$result"; print "</center></td>"; print "</tr>"; } php?> <center><font size="2"><a href="newliens.php" target="_blank">Ajouter votre lien</a></font></center> <SCRIPT LANGUAGE="JavaScript"> texte2 = 'CRAZYMANGA le site de reference !! Episode de grande qualite uniquement en Francais !! - '; x = texte2.length-1; place = 0; function defilStat() { if (place == texte2.length) { place = 0; } if (place <= x) { texteDef = texte2.substring((texte2.length-(x-place)),texte2.length) + texte2.substring(0,place); place++; } window.status = texteDef; tempo22 = setTimeout("defilStat()", 150); } </SCRIPT> </body> </html> |
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