Anas, > I am wondering if someone could shed some light on > this aspect of PHP. It might be something obvious, but > I am not able to figure it out. > > I have a function that returns a dynamically generated > HTML string. However, I need a way to let the caller > know if that function has failed. One way I thought > of, is to have an empty return: > > return; > > hoping that I could check for isset(). However, isset > reports "1". (In the C world, I could easily check for > NULL.) > Is there a way in PHP to return a failure flag back to > the caller? (Of course, I could use an argument as a > success flag. But, I am wondering if there is a way to > do it in the return variable.)
You could try: return FALSE; Remember that an IF condition can use == for 'same value' or === for 'same value and same type'. NB I do not recommend/condone the use of a single variable/return value to represent multiple data types, but if you're going to do it, this is about the best mechanism. Regards, =dn -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
