there is always a way.

$IP = $GLOBALS['SERVER_ADDR'];
$IP = $GLOBLAS['HTTP_HOST'];
$IP = $GLOBALS[HTTP_SERVER_VARS][HTTP_HOST];

do a print_r() on $HTTP_SERVER_VARS and see what you get  or use this
function

<?
function list_array ($array)
{
  foreach($array AS $key => $value)
  {
    echo "<b>$key:</b> $value<br>\n";
  }
}
list_array ($GLOBALS[HTTP_SERVER_VARS]);
?>

Jim Lucas

----- Original Message -----
From: "Dominique van der Wal" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, February 26, 2002 6:38 AM
Subject: [PHP] Damned HTTP_HOST


> Hi,
>
> I'm trying to find the HTTP_HOST adress of my website.
>
> I've try the followings :
>
> $HTTP_HOST  : nothing
> $ALL_HTTP["HTTP_HOST "] : nothing
> $_SERVER["HTTP_HOST "] : nothing
>
>
> But when I print $ALL_HTTP or $_SERVER, I obtain the followings lines :
>
> HTTP_ACCEPT_CHARSET iso-8859-1,*,utf-8
> HTTP_ACCEPT_LANGUAGE en,fr-BE
> HTTP_ACCEPT_ENCODING gzip
> HTTP_PRAGMA no-cache
> HTTP_ACCEPT image/gif, image/x-xbitmap, image/jpeg, image/pjpeg,
> HTTP_HOST 193.190.218.xxx
>
> So, how can I receive this damned HTTP_HOST adress ?
>
> Thank you in advance
> Dominique van der Wal
>
>
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>


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