David,
I hope that Robbie was able to solve your problem. But, if not, try
isolating the variables from the text in the header. e.g.
header("Location: ".$relative."/...?II=".$II."");
Hugh
----- Original Message -----
From: "David Robley" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Monday, February 18, 2002 6:18 PM
Subject: [PHP] Re: help with Header call
> In article <[EMAIL PROTECTED]>,
> [EMAIL PROTECTED] says...
> > Hello everyone,
> >
> > This is my first post to this list, so I hope that someone is awake
enough to help me out.
> >
> > I am new to PHP and I have a file that uses a command "header". It isn't
working like it is supposed to but I can't seem to figure out why. Below is
the last couple lines of the php file that is giving me trouble.
> >
> > while ($row=mysql_fetch_row($result)) {
> > $II=$row[0];
> > }
> >
> > Header("Location: $Relative/admin/upload.php?II=$II");
> >
> > Basically all it does when the whole file is called is return page does
not exist. The file that it refers to is there and the Var "$Relative" is
used in many other scripts with no probs so I don't think that is it. Is
passing the Var "$II" as part of the location incorrect?
> >
> > Any help is welcomed.
> >
> > If you need to see more of the script to understand what I am talking
about, I will post it.
> >
> > TIA
> > -Robbie
> >
>
> Try echoing the value of $II before the calling the header function; also
> try echoing the header parameter to see that it is what you expect it
> should be. Of course you might want to comment out the actual header line
> as you do the echo tests, as the output from the echos will cause an
> error from header()
>
> --
> David Robley
> Temporary Kiwi!
>
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