To correct the time, try this:
<?
$time = time();
echo "time = ".date("Y/m/d H:i:s",$time)."<br>";
$time = $time + (7*60*60);
echo "adjusted time = ".date("Y/m/d H:i:s",$time)."<br>";
?>
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Gaylen
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"Torkil Johnsen" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Hello...
>
> I have a field in my mysql database containing date&time on the format
> YYYY-MM-DD HH:MM:SS (24-hour format)
>
> Now. I want to output this as follows: DD.MM.YY at HH:MM:SS
> Currently I do this by this function:
>
> function convert_datetime($in){
> $return = substr($in,8,2) . "." . substr($in,5,2) . "." . substr($in,2,2)
.
> " at " . substr($in,11,8);
> return $return;
> }
>
> Is there a better way? Either with mysql or php?
> Now. Another problem. Since my webserver is in the states, and I live in
> Norway, I get a 7 hour time difference.
>
> So when I do date("Y-m-d H:i:s") I get a time that is 7 hours wrong.
> Any idea as to how I can correct this to be 7 hours later (that is: 12 in
> server time is really 19 where I live) in an easy way?
>
> THanks in advance,
> Torkil
>
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