Like this....
$myquery = "SELECT * FROM xpackage";
print "<p>myquery = $myquery</p>";
$myresult = mysql_query($myquery);
while($myrowz = mysql_fetch_row($myresult)){
print "<p>" . $myrowz[0] . "</p>";
}
[EMAIL PROTECTED] wrote:
>on 1/12/02 11:45 AM, sundogcurt at [EMAIL PROTECTED] wrote:
>
>>myquery = SELECT * FROM xpackage
>>Warning: Supplied argument is not a valid MySQL result resource in /path
>>to page with error/default.php on line 5
>>
>>Line 5 is this part
>>while($myrowz = mysql_fetch_row($myresult)){
>>
>
>this tells me that $myresult is not a valid mysql result resource
>identifier. how do you obtain $myresult?
>
>
> -- mike cullerton
>
>
>
