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* On 11-01-02 at 23:39 * Erik Price said.... > > EXCELLENT! > It worked perfect. > So $result can't be used twice -- I wonder if it somehow is altered by > the mysql_fetch_array() that is performed upon it. That's not it. Your first $result is a resource indicator (container for results) so if you re-assign it (put another value into it) it becomes useless as your while statement depends on it. Happy to help :) - -- Nick Wilson Tel: +45 3325 0688 Fax: +45 3325 0677 Web: www.explodingnet.com -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.0.6 (GNU/Linux) Comment: For info see http://www.gnupg.org iD8DBQE8P2pbHpvrrTa6L5oRAqWrAJ0RPOMtsW4IhBTkzKycyJnnZHwATACfTct6 Pi2wOViPXfXlpR1V3iw78Is= =RpGT -----END PGP SIGNATURE----- -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
