Another thing... if the $lineno variable isn't defined yet, maybe the parser first try a cast into __LINE__ type, so even if the assign procedure is called at the function call, the line is evaluated at the funcion definition step...
but maybe it's a bullship :-) J "Dav" <[EMAIL PROTECTED]> ha scritto nel messaggio [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > Well, I don't know either but I was thinking about that... > Usually this "$lineno = __LINE__" would be avaluated when the function is > called, this mean it gives the __LINE__ of the function call itself. > Why don't you try a more simple "include"/require instead of calling a > funcion ?(see example) > but maybe it will return the value "LINE 1" in the included file... I don't > know... > > that is: > > ...code... > include("line.php"); > ...code... > > line.php > -------- > echo(__LINE__); > "Jason G." <[EMAIL PROTECTED]> ha scritto nel messaggio > [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > > Hello, > > > > Does anyone know of a way, that from within a function, you can determine > > what line number and file the function was called on? > > > > I did try: > > function myfunc($lineno = __LINE__) > > { > > echo $lineno; > > } > > but this just outputted the very line that __LINE__ resides on. > > > > This would be very helpful in displaying sensible error messages, like the > > native php functions do. > > > > Thanks, > > > > -Jason Garber > > IonZoft.com > > > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
