RE: [PHP] Making a string from an Array

[Taylor, Stewart]

 $ignored = "";
 $include = "";

<snip>
 {
  $ignored.= $words[$i];
 }
 else 
 {
  $included.= $words[$i];

-Stewart
-----Original Message-----
From: Sam [mailto:[EMAIL PROTECTED]]
Sent: 25 October 2001 16:18
To: 'php'
Subject: [PHP] Making a string from an Array


Hi all, 
this may be an easy question, but I'm stuck...

how can this,

$words = explode(" ", $keywordText);

for ( $i = 0; $i < count( $words ); $i++ )
{
 if ($words[$i]=="on" OR $words[$i]=="the" OR $words[$i]=="in"
OR$words[$i]=="at" OR $words[$i]=="is" OR $words[$i]=="it")
 {
  $ignored[] = $words[$i];
 }
 else 
 {
  $included[] = $words[$i];
 }       
} 

How can I make $included and $ignored a string instead of an array. 

Thanks
Sam Rose

p.s. Also I'm only on the digest, so if you could reply directly to me as
well, that would be a bonus.

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