The only reason I could see that not working is if PHP is typecasting "test" to (int) in the second example...
$qty = "0"; (string) "test" = "test"; (string) "0" != "test" (evaluates true) $qty = 0; (int) "test" = 0; (when cast to int) 0 != 0 (evaluates false) e.g. By comparing an int to a string in the 2nd example, the string is casted to int, and the int cast of "test" is 0. -----Original Message----- From: Robin Chen [mailto:[EMAIL PROTECTED]] Sent: Thursday, October 25, 2001 4:06 AM To: [EMAIL PROTECTED] Subject: [PHP] = 0 and = "0" why does <? $qty = "0" ; if ($qty != "test") print "qty is not test"; ?> work properly but not the following <? $qty = 0 ; if ($qty != "test") print "qty is not test"; ?> Thanks, Robin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
