what's the error you're getting now?
if you aren't getting any error, but it just isn't working try something
like...(note that I haven't tested this code).
$drop_down_list = "<select name=\"select\">";
$link = mysql_connect ('localhost', '****', '****')
or die ("Could not select db");
mysql_select_db ('Heronsql')
or die ("Could not connect");
$query="select distinct HEI from heronuser";
$result = mysql_query ($query);
$num = mysql_num_rows($result);
for ($i = 0; $i < $num; $i++) {
$HEI = mysql_result($result, $i, "HEI");
$drop_down_list .= "<option value=\"$HEI\">$HEI</option>";
}
mysql_close($link);
$drop_down_list .= "</select>";
echo "$drop_down_list";
Cheers the noo,
Derek
----- Original Message -----
From: "George Pitcher" <[EMAIL PROTECTED]>
To: "Maxim Maletsky (PHPBeginner.com)" <[EMAIL PROTECTED]>;
<[EMAIL PROTECTED]>
Sent: Wednesday, September 26, 2001 3:42 PM
Subject: Re: [PHP] Building Dynamic Value list using ohp
> Thanks for everyone's help but this is still failing to work.
>
> Revised code is:
>
> <?php
> $link = mysql_connect ('localhost', '****', '****')
> or die ("Could not select db");
> mysql_select_db ('Heronsql')
> or die ("Could not connect");
> $query="select distinct HEI from heronuser";
> $result = mysql_query ($query); // I've also tried with ($query, $link)
> if(mysql_num_rows($result)) {
> // show all HEIs as options in select form
> while($row = mysql_fetch_row($result))
> {
> print("<option value=\"{$row[0]}\">{$row[0]}</option>");
> }
> }
> mysql_close($link);
> ?>
>
> Any more suggestions (please)?
>
> George
> ----- Original Message -----
> From: "Maxim Maletsky (PHPBeginner.com)" <[EMAIL PROTECTED]>
> To: "'George Pitcher'" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
> Sent: Wednesday, September 26, 2001 3:17 PM
> Subject: RE: [PHP] Building Dynamic Value list using ohp
>
>
>
> 1. this:
> print("<option value=\"$row[0]\">$row[0]</option>");
> should be this:
> print("<option value=\"{$row[0]}\">{$row[0]}</option>");
> or like this:
> echo '<option value="'.$row[0].'">'.$row[0].'</option>');
>
> The reason for it is that within double quote you can parse for 'simple'
> variables only (es: $var, not $var[]). Otherwise it gives you a parse
> error.
>
> 2. this:
> mysql_connect ('localhost', 'root', 'monty');
> better be this:
> mysql_connect ('localhost', '****', '****'); // for security
> reasons obviously, you don't wanna give the password our to the group,
> even so it is your local server (you might not be original with the
> password on production machines, no?)
>
>
> Hope it helps,
> Maxim Maletsky
>
> PHPBeginner.com
>
>
>
>
> -----Original Message-----
> From: George Pitcher [mailto:[EMAIL PROTECTED]]
> Sent: mercoledì 26 settembre 2001 15.31
> To: [EMAIL PROTECTED]
> Subject: [PHP] Building Dynamic Value list using ohp
>
>
> Hi all,
>
> I'm having a problem with dynamically building a value list.
>
> My code:
>
> <?php
> mysql_connect ('localhost', 'root', 'monty');
> mysql_select_db ('Heronsql');
> $query = ("select HEI from heronuser"); // LINE 22 on original script
> $result = mysql_query($query, $mysql_link);
> if(mysql_num_rows($result)) {
> // show all HEIs as options in select form
> while($row = mysql_fetch_row($result))
> {
> print("<option value=\"$row[0]\">$row[0]</option>");
> }
> }
> ?>
>
> But this generates:
>
> "Parse error: parse error in c:\program files\apache
> group\apache\htdocs\bizflyers\login.php on line 22"
>
> Any suggestions?
>
> Regards
>
> George
>
>
>
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