On Thu, Aug 09, 2001 at 01:08:33PM -0400, [EMAIL PROTECTED] wrote:
> Oops..(Hit send prematurely.)
>
> $currentmonth = date("m");
> $currentday = date("d");
> $year = date("Y");
> $newmonth = $currentmonth + 3;
> if ($newmonth > 12){
> $newmonth = $newmonth % 12;
> $year = $currentyear + 1;
> }
> $3months = date("Y-m-d",mktime(0,0,0,$newmonth,$currentday,$year));
>
> This should get me exactly 3 months later and also checks for if its a later
> month (oct, nov, or dec) then it goes to the next year. How could I check to
> see if the new date doesn't fall on Feb. 30th or whatever? If someone signs
> up on the 31st of a month it'll never end on a month with 31 days.
>
> Thanks,
> Pat
>
Nothing to worry about... PHP does it for you. You can try it you
know... Just use:
$currentmonth = 2; /* feb */
$currentday = 31;
$year = 2001; /* eg */
The output will then be:
2001-03-03
Ain't that most excellent?!?!
I should tell you though... that:
$3months = date("Y-m-d",mktime(0,0,0,$newmonth,$currentday,$year));
doesn't work. Obv. you haven't tried it. It produces an error (and
no date). Your variable name cannot begin with a number.
===== PHP Manual =====
A valid variable name starts with a letter or underscore, followed by
any number of letters, numbers, or underscores. As a regular expression,
it would be expressed thus:
'[a-zA-Z_\x7f-\xff][a-zA-Z0-9_\x7f-\xff]*'
===== =====
So I'd say: $threeMonths.
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