Okay, well I used the mysql_error() print-out, and it returned something weird: " Access denied for user: 'username@hostname' to database 'tablename' " This is incongruous because: 1. The uid/password set I am using has full privileges. 2. *tablename* is not a database (the code I listed in my previous email is syntactically identical to the script)-- it's a table. Why is this happening to me?!?! ;) Note: forwarded message attached. __________________________________________________ Do You Yahoo!? Make international calls for as low as $.04/minute with Yahoo! Messenger http://phonecard.yahoo.com/
or, echo $sql and copy/paste it into an sql client and see what it tells you. on 7/31/01 4:21 PM, Philip Olson at [EMAIL PROTECTED] wrote: > Try putting mysql_error() in your die statements so : > > or die(mysql_error()); > > and see what it tells you. > > Regards, > Philip > > > On Tue, 31 Jul 2001, CGI GUY wrote: > >> Is there anything (add. parameters, etc.) that I'm >> missing that would possibly explain why the following >> code won't execute? >> -- mike cullerton -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
-- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
