On Thu, May 3, 2012 at 9:12 PM, Ron Piggott
<[email protected]> wrote:
> I need to access a FUNCTION I programmed within a different FUNCTION. Are
> these able to be passed like a variable? Or are they able to become like a
> $_SESSION variable in nature? How am I able to do this?
>
> I am essentially programming:
>
> ===
> function name( $flag1, $flag2 ) {
>
> # some PHP
>
> echo name_of_a_different_function( $flag1 , $flag2 );
>
> }
> ===
>
> The error I am receiving is “Call to undefined function
> name_of_a_different_function”
Where is name_of_a_different_function defined? If it is somewhere in
the same file as name, that shouldn't be a problem, provided it is
defined in the same namespace/scope as name. If it is defined in a
different file, you need to include that file before you make the echo
statement.
For example:
function func1 ($flag1, $flag2) {
# blah blah
echo func2($flag1, $flag2);
}
function func2 ($flag1, $flag2) {
#blah blah
return "some string value";
}
in the same file should be just fine. It doesn't really matter what
order func1 and func2 are declared in.
However, if func2 is defined in some_other_file.php, you need to
include it in this_file.php (where func1 is defined) first:
this_file.php:
include('some_other_file.php');
function func1 ($flag1, $flag2) {
#blah blah
echo func2 ($flag1, $flag2);
}
some_other_file.php:
function func2 ($flag1, $flag2) {
#blah blah
return "some string value";
}
If func2 is a method for an object/class, you'll have to access it
that way in func1:
this_file.php:
include('MyClass.php');
function func1 ($flag1, $flag2) {
# blah blah, instantiate object?
$myobj = new MyClass();
echo $myobj->func2 ($flag1, $flag2);
}
MyClass.php:
class MyClass
{
function func2 ($flag1, $flag2) {
#blah blah
return "some string value";
}
}
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