On 10 March 2011 11:07, <rob...@myself.com> wrote:
> Thank you, that did get me past that part!
>
> Had also to put in else statement to call Email function, without doing so
> the mail was sent even though giving error
>
> Robert
>
>
>
>
>
>
>
> -----Original Message-----
> From: Louis Huppenbauer <louis.huppenba...@gmail.com>
> To: rob...@myself.com
> Cc: php-general@lists.php.net
> Sent: Thu, Mar 10, 2011 11:38 am
> Subject: Re: [PHP] Issue with Quick Email validation
>
>
> try != instead of ==, that should do the trick.
>
>
>
> 2011/3/10 <rob...@myself.com>:
>
>> Hi,
>
>> I'm newbie to PHP and this list, possible not a new question so forgive me if
>
> it's a repeat
>
>> I have a form where I want the submitter Email ID to only be from one domain
>
>>
>
>> Here's the part I'm having issues with
>
>>
>
>> $domain = explode( "@", $who);
>
>> if ( $domain[1] == "company.com") {
>
>> echo $domain[1];
>
>> echo("<h3>Email invalid.</h3>");
>
>> exit;
>
>> }
>
>>
>
>> First Echo is just for me to check
>
>> I type in a correct Email ID, say m...@company.com
>
>>
>
>> The return of this is:
>
>>
>
>> company.com
>
>> Email invalid.
>> As far as I can see this if statement should not fall in, what am I missing?
Why bother asking for the entire address? Just ask for the name part
and display the domain name on the form?
<label for="email">Enter your email address: <input type="text"
name="email" id="email" />@company.com</label>
sort of thing.
--
Richard Quadling
Twitter : EE : Zend
@RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY
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