On Sat, Jul 11, 2009 at 19:57, Govinda<govinda.webdnat...@gmail.com> wrote:
I have been using PEAR's tableInfo() to remind myself about the columns in the table.. but now I want to see as much data as possible about the table and its contents *without* using PEAR. (I.e. just using built in stuff for
mysqli.)

   This is not mysqli_#() directly, but just mocked up here in this
email.  Not guaranteed to work, but should give you the right idea at
least.  ;-P

<?php
include('inc/config.php'); // Your configuration
include('inc/db.php'); // Your database connection info

$sql = "SHOW TABLES";

$result = mysql_query($sql);

foreach(mysql_fetch_assoc($result) as $k => $v) {
       $ssql = "DESCRIBE ".mysql_real_escape_string($v);
       $rresult = mysql_query($ssql);
       echo "<b>".$k."</b>:<br />\n";
       echo "<pre>\n";
       print_r(mysql_fetch_assoc($rresult));
       echo "</pre>\n";
       echo "<br />\n";
}
?>


Dan I get roughly the idea, but alas I am stumped so easily in this new ocean.. it frustrates me.

I have this code:

        $db_billing=mysqli_connect(localhost,metheuser,mypass,billing);
if (mysqli_connect_error()) { die("Can't connect: " . mysqli_connect_error()); }
        //$dbname = 'billing';
        $sql = "SHOW TABLES";
        
        $result = mysql_query($sql); // line 53
        
        foreach(mysql_fetch_assoc($result) as $k => $v) {  // line 55
        $ssql = "DESCRIBE ".mysql_real_escape_string($v);
        $rresult = mysql_query($ssql);
        echo "<b>".$k."</b>:<br />\n";
        echo "<pre>\n";
        print_r(mysql_fetch_assoc($rresult));
        echo "</pre>\n";
        echo "<br />\n";
        }

Which is just giving these errors:

Warning: mysql_query() [function.mysql-query]: Access denied for user 'meee'@'localhost' (using password: NO) in /home/meee/public_html/ somedir/test.php on line 53

Warning: mysql_query() [function.mysql-query]: A link to the server could not be established in /home/meee/public_html/somedir/test.php on line 53

Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in /home/meee/public_html/somedir/test.php on line 55

Warning: Invalid argument supplied for foreach() in /home/meee/ public_html/somedir/test.php on line 55

--
I am looking forward to when I have enough of my bearings that I can just cruise around all the various docs and figure out my own answers. Now there are just so many unknowns, I often can't tell which way to even look to solve the issues.
-G


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