Re: [PHP] image button troubles

[Kurt Lieber]

Are you entering the fully-qualified URL?  The following works perfectly on
my machine:

<?php
    $tempVar = getImageSize("http://i.cnn.net/cnn/images/main/cnnlogo.gif";);
    echo $tempVar[3];
?>

(it's the main logo for cnn.com)

--kurt
----- Original Message -----
From: <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, July 03, 1979 4:44 PM
Subject: Re: [PHP] image button troubles


> on 7/3/01 7:52 PM, Kurt Lieber at [EMAIL PROTECTED] wrote:
>
> > I had a similar problem a while back that I solved by isolating my
> > variables.  Such as:
> >
> > <?php echo "x = " . $mapclick_x . "and y = " . $mapclick_y . ""; ?>
> >
> > As for why it's happening, I'm not sure.
>
>
> Wow, that fixed it!  Though it turns out I was mistaken in thinking I'd
> fixed the bug... it still says it's "unable to open" the image I give
it...
>
> hmmm..
>
> Susan
>
>
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