Try
$text = "Joe of Egypt";
$sql = "SELECT title FROM book WHERE title LIKE '$text'";
$result = mysql_query($sql);
If(mysql_num_rows($result) >= '1')
{
while ( $row = mysql_fetch_array($sql) ) {
echo("<P>" . $row["title"] . "</P>");
}
}
My Ideas my not make some people happy with my design but I use it and it
works very well
-----Original Message-----
From: PJ [mailto:af.gour...@videotron.ca]
Sent: Thursday, February 26, 2009 5:07 PM
To: php-general@lists.php.net
Subject: [PHP] verify text in field
Is there a shorter way of determining if a field contains text?
This works but I wonder if I can K.I.S.S. it? I really only need to know
if there is or is not a field containing the text specified. I don't
need to see it.
<?php
// Request the text
$text = "Joe of Egypt";
$sql = "SELECT title FROM book WHERE title LIKE '$text'";
$result = mysql_query($sql);
if (!$result) {
echo("<P>Error performing query: " .
mysql_error() . "</P>");
exit();
}
// Display the text
while ( $row = mysql_fetch_array($result) ) {
echo("<P>" . $row["title"] . "</P>");
}
if ($row["title"] == "")
echo ("Empty!")
?>
--
Phil Jourdan --- p...@ptahhotep.com
http://www.ptahhotep.com
http://www.chiccantine.com
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