On Mon, Nov 3, 2008 at 2:46 PM, Ashley Sheridan <[EMAIL PROTECTED]>wrote:
> On Mon, 2008-11-03 at 15:56 +0100, Anders Norrbring wrote:
> > > Anders Norrbring wrote:
> > >
> > > > I've been staring myself blind, so now I don't get anywhere, please
> > > do
> > > > advice..
> > > >
> > > > I have a web page printed with PHP, in a table I need to display
> > > > images that are stored in a SQL DB.
> > > > Getting the images into variables isn't an issue at all, but how do I
> > > > output it?
> > > > This is what I want to accomplish:
> > > >
> > > > <tr><td>Current image:</td><td> - THE IMAGE HERE - </td></tr>
> > > >
> > > > Starting to pull my hair..
> > > > Anders.
> > >
> > > <img src="fetchimg?id=<nnnnn>"/>
> > >
> > > fetchimg.php:
> > >
> > > header('Content-Type: image/jpeg');
> > > $img=<fetch from db>;
> > > print $img;
> >
> >
> > True Per, but I would prefer one single file in this case..
> >
> > Anders.
> >
> >
> You can have the image script as part of the same PHP file, by checking
> to see if it is being called for an image rather than a normal page, but
> it just makes things more convoluted. Also, the base64 method will not
> work in IE. I had a similar problem at work that could only be solved by
> using a separate script to output the image. It can't be streamed inline
> in a consistent manner.
>
>
> Ash
> www.ashleysheridan.co.uk
>
>
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>
I too prefer to have the image called from a separate page.
<img src='getimage.php?id=12345'/>
That way if the images are of differeing types (tiff/png/jpg/etc) I can
locate all the handling code in the getimage.php file and its becomes the
one place to handle this kind of stuff
--
Bastien
Cat, the other other white meat
