When I have => $data_type in there my column title values for $field_name
display correctly. If I take out => $data_type it displays the the column
type. IE SQLNUMINT SQLCHAR...instead of the column title.
On 6/23/08, Daniel Brown <[EMAIL PROTECTED]> wrote:
>
> On Mon, Jun 23, 2008 at 1:46 PM, Dan Shirah <[EMAIL PROTECTED]> wrote:
> >
> > if($numberFields) { // Check if we need to output anything
> > $types = ifx_fieldtypes($query);
> > if (isset($types)) {
> > foreach($types as $field_name[] => $data_type) {
> > }
> > }
>
> Is there a particular reason you're telling PHP that, "for each
> $types variable, set this key of the $field_name array to equal
> $data_type, and do nothing else about it"?
>
> Is this what you meant to do for some reason?
>
> <?php
>
> if(isset($types)) {
> foreach($types as $field_name => $data_type) {
> $$field_name = $data_type;
>
> // Or should it be something like this?
> $column_names[] = $field_name;
> }
> }
>
> $headers = join(',', $column_names)."\n";
> ?>
>
>
> --
> </Daniel P. Brown>
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