> One could ask if it would just pass to > the constructor, but it doesn't. I don't know if there's a technical > reason > for that or if just no one implemented it, but the short answer is "The > language doesn't do that."
That's what i was asking about, when trying to "cast" something into a non native type ( ie a class ), just fire the constructor. Would'nt it be great ? $myvar=(array) somefunc(); $myvar=(myarrayextented) somefunc(); ( what should be exactly the same as ) $myvar=new myarrayextented(somefunc()); But with a lot more of coolness ! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
