I forgot to tell you that I have to use PHP4.2 because of my web provider.
Anything besides of _clone?

SanTa

  ----- Original Message ----- 
  From: Hamza Saglam 
  To: "Sándor Tamás (GMail)" 
  Sent: Tuesday, August 07, 2007 10:49 AM
  Subject: Re: Object reference into variable?


  You may find the following article interesting. It talks about object 
  cloning, which I think what you are after...

  http://www.phpfreaks.com/phpmanual/page/language.oop5.cloning.html


  Regards,
  Hamza.


  ""Sándor Tamás (GMail)"" <[EMAIL PROTECTED]> wrote in message 
  news:[EMAIL PROTECTED]
  > Hello,
  >
  > I have a question (what a surprise :-) )
  >
  > I browsed the archives, but didn't find what I'm looking for.
  > I have an object instance stored in some variable (like $myobject). I want 
  > to save this instance into another variable (like $tempobject). I thought, 
  > this will be the way:
  >  $myobject = new MyObject();
  >  $tempobject = $myobject;
  > (or I tried this too:
  >  $tempobject = &$myobject)
  >
  > None of them worked, like I cannot access methods in the object:
  >  $tempobject->Foo()
  > gives me an error: calling to method on a non-object variable.
  >
  > How can I tell PHP that $tempobject is a class instance of MyObject, and 
  > that I can use it's methods?
  >
  > Thanks,
  > SanTa 


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