# [EMAIL PROTECTED] / 2006-12-06 23:51:45 +0200:
> >> How can I ensure that a variable contains a postive integer number?
> >> I'm currently using this code:
> >>
> >> $number=(10000-$number);
> >> $number=(10000-$number);
> >> if ( $number<1 ) { $number=1; }
> >>
> >> But I'm sure that there is a better way. What would that be?
 
> Thanks. As the 'number' is used in a for loop, it actually is alright
> if it is a float. I just added a check that the number is indeed >=1,
> otherwise I set it to 1. Good enough for this project, anyway... :)

    $number = max(intval($number), 1);

-- 
How many Vietnam vets does it take to screw in a light bulb?
You don't know, man.  You don't KNOW.
Cause you weren't THERE.             http://bash.org/?255991

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