Jochem Maas wrote:
Arpad Ray wrote:
return preg_replace('#%5[bd](?=[^&]*=)#ei', 'urldecode("\0")', $s);
could you explain your regexp - I'd like to replace my version with
your (if for no other reason than that shorter code is easier to read than
longer code!) BUT until I really understand your regexp I'd feel 100%
comfortable
making the replacement.
Basically, if we find a '=' before a '&' then we know we're in the key.
The (?=) is a positive assertion, which says that the bracket must be
followed by a '=', optionally with any characters except '&' in between.
Here's the pattern with comments:
~
%5[bd] # the bracket
(?= # must be followed by
[^&]* # any characters except "&"
= # then a "="
)
~eix
Regards,
Arpad
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