On 10/5/06, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
Using this string: "{$var1: $var2}" ....of course it doesn't work as some might expect.But why in the name of [whatever, too many to list] doesn't this one below work? "\{$var1: $var2}" If \ is an escape character why does it also appear in the string output? Why does the above \ escape {$var1 and not only the {? Miserable.
First up: http://uk2.php.net/manual/en/language.types.string.php#language.types.string.syntax.double Excerpt: Again, if you try to escape any other character, the backslash will be printed too! Before PHP 5.1.1, backslash in \{$var} hasn't been printed. Then: http://uk2.php.net/manual/en/language.types.string.php#language.types.string.parsing.complex Excerpt: Since you can't escape '{', this syntax will only be recognised when the $ is immediately following the {. (Use "{\$" to get a literal "{$"). Does that help? HTH, John W -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
