[PHP] optional argument when creating a function

[D A GERM]

I'm throwing a warning on a function I created. I
thought a & in front of the argument was supposed to
make it optional. Is there something else I need to do
make that argument optional?

<CODE>
//I simplified the code
function doEmail($username, &$link)
{
  if (isset($link))
  {
     print "$link $username";
  }
  else
  {
     print "$username";
  }
}

doEmail($arg1);
doEmail($arg1, $arg2);
</CODE>

Here is the error:
Warning: Missing argument 2 for doemail() in
/srv/www/htdocs/test-a/staff/email_scramble.php on
line 24

thanks in advance for any help.

--
D. Aaron Germ
Scarborough Library, Shepherd University
(304) 876-5423

"Well then what am I supposed to do with all my creative ideas- take a bath and wash 
myself with them? 'Cause that is what soap is for" (Peter, Family Guy)

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