Linda H wrote:
Where is fahrenheit? change the input name...fahreheit is here: <? $fahr = $_GET['fahrenheit']; if (is_null($fahr)){ echo 'fahr is null';} $> The error was on the line: $fahr = $_GET['fahrenheit']; Linda
Have you checked that the name is spelt correctly in your HTML form? I (and this is jus a preference) do: $var = (isset ($_GET['var'])) ? $_GET['var'] : null; HTH, Mikey -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
