On 5/9/2005 9:47:50 AM, Burhan Khalid ([EMAIL PROTECTED]) wrote:
> Ryan A wrote:
>
> > <clip>
>
> > Your looking at something like. For ages between 21 and 23
>
> >
>
> > $Upper = date("m-d-Y", mktime(0,0,0,date("m"),date("d"),date("y")-22));
>
> > $Lower = date("m-d-Y", mktime(0,0,0,date("m"),date("d"),date("y")-23));
>
> >
>
> > $sql =
> "SELECT field1,field2,field3 FROM `table_name` WHERE `age`
> > BETWEEN " .
> $Lower . " AND " . $Upper;
>
> >
>
> > $result = myqsl_query($sql);
>
> >
>
> > etc....
>
> >
>
> > Cheers
>
> > Richard
>
> > </clip>
>> If you are lucky enough to use MySQL 5 *grin* you can simply do : > > SELECT field1,field2 FROM `sometable` WHERE > TIMESTAMPDIFF(YEAR,NOW(),`age`) = 22 > > to find all 22 year olds. Hey, Luck and me? You dont know who you are talking to my friend....I am still on mysql 3.23 not even 4.1 !!! :-D Cheers, Ryan -- No virus found in this outgoing message. Checked by AVG Anti-Virus. Version: 7.0.308 / Virus Database: 266.11.6 - Release Date: 5/6/2005 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
