Well, unless I'm misstaken, the '=& new' should only be used once with every
class, so your code doesn't really make sense. The reason is that you are
trying to set the A to the new a, not $a to the new a.. Now, A couldn't get
changed I suppose, so therefore, $arr[1] will be a reference to $a, which is
still a reference to A.. Something like that.. I can only guess it'll work
as expected ("(wsx)(wsx)") if you change =&new to =new..-- // DvDmanDT MSN: dvdmandt€hotmail.com Mail: dvdmandt€telia.com "News.Php.Net" <[EMAIL PROTECTED]> skrev i meddelandet news:[EMAIL PROTECTED] > <? > > class A > { > var $name; > function A($str) > { > $this->name = $str; > } > } > > $arr = array(); > > //Put to array to objects of class A, > // where their attribute A::a is assigned a different value > //objects are assigned to an array by reference > > $a = &new A("qaz"); > $arr[0] = &$a; > > $a = &new A("wsx"); > $arr[1] = &$a; > > > //But watch the output!!! > // It is "(qaz)(qaz)", which means that the attribute of a first > // object assigned to array is outputted!!! WHY?!?!!! > foreach($arr as $a) > { > echo "(".$a->name.")"; > } > ?> -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
