Chris is quoted as saying on 11/30/2004 2:53 PM:
imagesx() requires an image resource , not a file path. so you'd need
to use one of the imagecreatefrom* functions to create the resource.
But it looks like all you want is the width and height of an image....
If so use get imagesize() ( which *does* except a pathname, not a resource)
Chris
http://www.php.net/image
http://www.php.net/getimagesize
<SNIP>
I had looked at get image size, but thought the other would be quicker... ARGH.
$a=getimagesize($path);
$width = $a[0];
$width = $width/2;
$height = $a[1];
$height = $height/2;
works!!
--
Robert Sossomon, Business and Technology Application Technician
4-H Youth Development Department
200 Ricks Hall, Campus Box 7606
N.C. State University
Raleigh NC 27695-7606
Phone: 919/515-8474
Fax: 919/515-7812
[EMAIL PROTECTED]
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
