Probably, thank you :) "Pluance" <[EMAIL PROTECTED]> skrev i meddelandet news:[EMAIL PROTECTED] > You mean this? > > foreach ($arr as $key => $value) { > echo "\$arr[${key}] = $value"; > } > > On Wed, 17 Nov 2004 14:05:23 +0100, Peter Lauri <[EMAIL PROTECTED]> wrote: > > Hey :) > > > > But what if the array have a unordered keystructure? What your loop do is > > to call the value with key $i, or am I wrong? What if the keys are strings? > > > > - Best Of Times > > /Peter Lauri > > > > > > "Dirk Kredler" <[EMAIL PROTECTED]> skrev i meddelandet > > news:[EMAIL PROTECTED] > > > > > > > hey :) > > > > > > i use for this reason: > > > > > > for($i= 0, $size= sizeof($arr); $i < $size; $i++) { > > > echo $arr[$i]; > > > } > > > > > > Peter Lauri: > > > > Best groupmember, > > > > > > > > For the moment when I loop an array I use something like this: > > > > > > > > reset($arr); > > > > while($a=each($arr)) { > > > > echo $a['value']; > > > > } > > > > > > > > But the each() function genereates a array with four elements > > (0,1,value, > > > > key), I am only interested in the "value". > > > > > > > > -- > > PHP General Mailing List (http://www.php.net/) > > To unsubscribe, visit: http://www.php.net/unsub.php > > > >
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