Linux. PHP5. Why does this fail when using an array element, but using a variable will work? Why should PHP care what the variable is I'm trying to store into?
list($bar['CompanyCode'], $CompanyDB) = mysql_fetch_row($sth); But this works: list($foo, $CompanyDB) = SQL_ROW($sth); And of course I'd have the extra... $foo = $bar['CompanyCode']; -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
