Henri,
Try:
if($HTTP_POST_VARS['submit'])
{
for($i = 1; $i < 51; $i ++)
{
if (${lottery_number.$i} == 'on')
echo "Number selected is $i";
}
}
else
{
echo "<form action='".$PHP_SELF."' method='post'>";
for($i = 1; $i < 51; $i ++)
{
echo "Number $i: <input type='checkbox' name='lottery_number".$i."'><br />";
}
echo "<input type='submit' name='submit' value='Enter Numbers'>";
echo "</form>";
}
HTH,
Michael Egan
> -----Original Message-----
> From: Henri Marc [mailto:[EMAIL PROTECTED]
> Sent: 21 July 2004 12:33
> To: [EMAIL PROTECTED]
> Subject: Re: [PHP] Problem of a beginner with Array[Scanned]
>
>
> Hello,
>
> Thank you very much for all the people who replied me
> so fast.
> Unfortunately I still have a problem with that part.
>
> "Matt M." <[EMAIL PROTECTED]> wrote:
>
> > Now, I want to know which numbers have been checked
> by the player.
> > I have a :
> > "input name="Grid1" type="checkbox"
> > for the first grid. Grid2 for the grid #2...
> >if the user checks any Grid1[] boxes then
> $_POST['Grid1'] will be an array and so on.
>
> I want to avoid to have to name each check box like
> this:
> Grid[1][1] //1st checkbox of the first grid
> Grid[1][2] //2nd checkbox of the first grid and so on
>
> I would prefer to have if possible:
> input name="Grid1[]" type"checkbox" //1st grid, 1st
> checkbox
> input name="Grid1[]" type"checkbox" //1st grid, 2nd
> checkbox...
>
> That's what Matt M proposed.
> If I do: echo $_POST['Grid1'];
> I have "on" as a result and not a value. I also tried
> with echo $_POST['Grid1[]']; and other similars but I
> have an error message "undefined index", or "array".
>
> Thanks again.
>
> Dave
>
>
>
>
>
>
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