It's still a member, it just can't be accessed by the sub-class's
methods. If you call the parent's methods or a method in the parent is
called that isn't defined in the subclass, the private property is
still there are still used as normal.
On Wed, 23 Jun 2004 18:35:14 -0400, Chris <[EMAIL PROTECTED]> wrote:
>
> ok, i understand now that private members are NOT inherited. i guess it
> was just throwing me off that var_dump()/print_r() display the parents
> private member, even tho its not really a member of the subclass.
>
> thanks
>
> Marek Kilimajer wrote:
> > Chris wrote --- napísal::
> >
> >> if anyone can, would you please explain why the below code does what
> >> it does? I would expect $this->test in TestInstance to refer to the
> >> inherited $test from Test. Using php5RC3. Thanks.
> >>
> >> <?php
> >> abstract class Test {
> >> private $test;
> >> abstract public function addToTest($i);
> >> }
> >>
> >> class TestInstance extends Test {
> >> public function __construct() {
> >> $this->test = 0;
> >> }
> >>
> >> public function addToTest($i) {
> >> $this->test += $i;
> >> }
> >> }
> >>
> >> $t = new TestInstance();
> >> $t->addToTest(3);
> >>
> >> var_dump($t);
> >>
> >> // test var SHOULD be private
> >> echo "private test (shouldn't be able to access it directly, but i
> >> can): ".$t->test."\n\n";
> >>
> >> /*
> >> output
> >> -------------------------------
> >> object(TestInstance)#1 (2) {
> >> ["test:private"]=>
> >> NULL
> >> ["test"]=>
> >> int(3)
> >> }
> >> private test (shouldn't be able to access it directly, but i can): 3
> >> */
> >> ?>
> >>
> >
> > The variable is private for Test, so TestInstance does not have access
> > to it. By assigning 0 to $this->test in the constructor of TestInstance,
> > you create a new property of TestInstance that is public (the default).
> >
> > var_dump() shows it clearly:
> > object(TestInstance)#1 (2) {
> > ["test:private"]=> NULL <---- belongs to Test
> > ["test"]=> int(3) <---- belongs to TestInstance
> > }
>
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>
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