Phil Ewington - 43 Plc wrote on donderdag 10 juni 2004 12:58: > Hi All, > > Can anyone tell me how to pass arguments to a PHP script from the > command line? I know I need to use the -args option but how exactly, > I have tried the following... > > /usr/bin/php myscript.php -args key=value
You don't have to call the -args argument. just run the script from command line like this: php myscript.php value Where value is the argument you want to use in the script. These arguments are stored in an arrray ($argv). Do a print_r($argv) and you can see the content. > > but this does not work, the script executes but key is not available > as $_GET["key"] in my script. Any pointers will be much appreciated. > > TIA > > Phil. > > --- > Phil Ewington - Technical Director > > 43 Plc - Ashdale House > 35 Broad Street, Wokingham > Berkshire RG40 1AU > > T: +44 (0)1189 789 500 > F: +44 (0)1189 784 994 > E: mailto:[EMAIL PROTECTED] > W: www.soyouthink.com > > --- > Outgoing mail is certified Virus Free. > Checked by AVG anti-virus system (http://www.grisoft.com). > Version: 6.0.701 / Virus Database: 458 - Release Date: 07/06/2004 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
