On 30 avr. 04, at 11:31, Torsten Roehr wrote:
"Frederic Noyer" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED]
On 30 avr. 04, at 11:00, Torsten Roehr wrote:
I think this is correct because the 3 key/value pairs from the first
array
are NOT in the second one. I think the combination of key and value are
relevant for array_diff().
As I have understand only the array_diff_assoc function does that. see php.net:
"Description array array_diff_assoc ( array array1, array array2 [, array ...])
array_diff_assoc() returns an array containing all the values from array1 that are not present in any of the other arguments. Note that the keys are used in the comparison unlike array_diff()."
So array_diff() seems to be for arrays where the key is not defined so that
only values are recognized.
Regards, Torsten
Any ideas what this implies in termes of code ? You mean, I should not fill my array with values this way ? "$arr2[] = (string) $recListAut['aut_id'];"
Because this is precisely the way to fill it without specifying the key. see www.php.net: http://ch2.php.net/manual/en/language.types.array.php
Regards, Fred
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