[snip] ok, this same query, works EVERYWHERE ELSE, why won't it work now? it returns to me: Warning: Supplied argument is not a valid MySQL result resource
$query_result = mysql_query("SELECT * FROM AotH_Users"); while ($row = mysql_fetch_array($query_result, MYSQL_NUM)){ [/snip] When are you guys going to learn about error reporting, huh? Try this (verbose) $query = "SELECT * FROM AotH_Users"; if(!($result = mysql_query($query, connection_string))){ echo mysql_error(); exit(); } -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php