[PHP] Re: trying to output a hyperlink

[Andy Ladouceur]

When in doubt, view source. :) As John has already mentioned, you need 
text between the two tags to actually display in the browser. You 
probably would've seen your mistake a lot sooner if you viewed the page 
source when you first tried it out.

Also, you can save yourself some time using PHP's shorthand 
concatenation operator.

> <td><?php $link = '<a href="' ;
>               $link = $link . $row[2] . '">' ;
>               $link = $link . '</a>' ;
>               echo $link ; ?></td>
Turns into:

<td><?php $link = '<a href="';
                $link .= $row[2] . '">';
                $link .= 'Click here</a>';
                echo $link; ?></td>
Although, it could be shortened even more, to:

<td><?php $link = "<a href=\"".$row[2]."\">Click here</a>";
        echo $link;?></td>
But I imagine you're doing it with more lines for legibilities' sake.

Andy

Damian Brown wrote:
<td><?php $link = '<a href="' ;
              $link = $link . $row[2] . '">' ;
              $link = $link . '</a>' ;
              echo $link ; ?></td>
is not working, I want to output $row[2] as a hyperlink
as it is the refering URL, but the above is just showing blank in the
output, with no link and no text in the output table
--
www.phpexpert.org/truefaith.htm
"True Faith is not just when you believe in God and yourself, it is when
others begin to believe in you as well" - Damian John Paul Brown 2004
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