[PHP] Re: Having trouble formatting width using printf() and default spaces

[David Scott]

I tried your method and it's a nice variation, though it leaves me with 
two issues:

1. I'd like the numbers to be right-aligned.
2. I'd still like to understand why the default padding of spaces isn't 
working for printf(). If I could get printf() to pad with spaces, it 
would be exactly what I'm after.

Jason Barnett wrote:
David Scott wrote:

I'm using a for() loop to generate random die rolls. I'd like the 
numbers to be formatted in a grid.


In a grid... like an HTML table?  You could something like:
$row = 20;
$col = 5;
echo '<table>';
for ($i = 1; $i < $row; $i++) {
    echo '<tr>';
    for ($j = 1; $j < $col; $j++) {
        echo '<td>'.rand(1, $sides).'</td>';
    }
    echo '</tr>';
}
echo '</table>';
for ($i = 0; $i < 100; $i++) {
    if (!($i % 5)) {
        print("<br />");
    }
    printf("%'.10u", rand(1,$sides));
}
Currently, I'm padding with '.', but I'd like to pad with the default 
spaces.

For example, printf("%10u", rand(1,$sides)); Except the numbers end up 
like,

7 10 14 19 3
4 6 16 13 2
etc.
Why is it that when I leave out the padding character, the output 
isn't padded?
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