function called_from_file(){
$backtrace = debug_backtrace();
print $backtrace[0]['file'];
}check: http://www.php.net/manual/en/function.debug-backtrace.php
Samuel Ventura wrote:
Hi there
I have 2 scripts:
//////////////////////////////// <?php /* test1.php */
function called_from_file(){ print __FILE__ } ?>
/////////////////////////////// <?php /* test2.php */
include("test1.php");
called_from_file();
?>
///////////////////////////////// I get the output test1.php
what I need is to detect the name of the script
from which I called the function, (test2.php) in this
case.
For this application, it is not practical to pass an aditional parameter to the function specifying the caller, i need independence.
Any ideas?
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