Re: [PHP] Dynamically Created Arrays

[Marek Kilimajer]

This should be what you need:

if(!is_array($conf[$name])) $conf[$name] = array($val);
else $conf[$name][] = $val;
Cameron B. Prince wrote:

Hey guys,

I'm making progress on my perl to PHP conversion project but I need some
help...
I have a configuration table in MySQL made up like this:

CREATE TABLE config (
  code mediumint(9) NOT NULL auto_increment,
  site varchar(32) NOT NULL default '',
  name varchar(64) NOT NULL default '',
  value varchar(128) NOT NULL default '',
  seq smallint(4) default NULL,
  PRIMARY KEY  (code)
) TYPE=MyISAM;
It has data like this:

| 1  | site1 | homedir   | /var/www/htdocs/site1 | NULL |
| 2  | site1 | groupname | Group1                | 1    |
| 3  | site1 | groupname | Group2                | 2    |
I use this query to get the configuration data:

SELECT name, value
FROM config
WHERE site = '$site'
ORDER BY name, seq
What I want to create is an array of arrays like this:

$conf[$name][] = $val;

or

array_push($conf[$name], $val);

So I end up with something like:

$conf[homedir][0] = /var/www/htdocs/site1
$conf[groupname][0] = Group1
$conf[groupname][1] = Group2


If I were still in Perl-land, I'd use a hash of arrays and push things into
it, but I don't seem to have that option now and I keep getting "Use of
undefined constant name" errors.
Am I going about this in the right way? Any help would be greatly
appreciated.
Thanks,
Cameron
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