Hello

I think there is some problem with the permission.
Even if I execute a command like -

echo ( "start" );
exec ( "pwd" );
echo ( "end" );

the output is - startend

shouldnt be pwd showing the present working directory
to me.

Karam
--- Jason Wong <[EMAIL PROTECTED]> wrote:
> On Saturday 06 December 2003 12:56, Karam Chand
> wrote:
> 
> > looking at manuals and help and some help from
> you. i
> > wrote the attached code-
> >
> >   error_reporting (E_ALL);
> >   ini_set('display_errors', 1);
> >
> >   $result = `./myapp`;
> >   print_r ( $result );
> >
> >   echo ( "2" );
> >
> >   exec("./myapp",$result);
> >   print_r($result);
> >
> > It is returning output
> >
> > 2Array ( )
> >
> > which means the array is empty !!!
> >
> > it should have outputted ErrorError
> 
> I believe you mean to say that it should output:
> 2Error
> 
> OK, does your "myapp" program dump its output to
> STDOUT?, Remember exec() only 
> captures STDOUT.
> 
> > Both the php and the binary exsits in
> > http://www.mydomain.com/mgmt/
> 
> One way to satisfy yourself that exec() is working
> is to create a small test 
> program, eg:
> 
> ----8<-------------
> #!/bin/bash
> echo "test"
> ----8<-------------
> 
> Then exec() it.
> 
> > Can I send you the binary so that you can check it
> > out?
> 
> No thank you.
> 
> -- 
> Jason Wong -> Gremlins Associates ->
> www.gremlins.biz
> Open Source Software Systems Integrators
> * Web Design & Hosting * Internet & Intranet
> Applications Development *
> ------------------------------------------
> Search the list archives before you post
> http://marc.theaimsgroup.com/?l=php-general
> ------------------------------------------
> /*
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