and in your example I have 4 elements in the array, not three.
Array
(
[0] => 20031202
[1] => 2003
[2] => 12
[3] => 02
)
I suppose something like preg_match("/(\d{4})(\d{2})(\d{2})/", $mydate, list($y,$m$d));
Is vaguely what I am gunning for.
And substr()...
$date = 20031202;
$year = substr($date,0,4);
$month = substr($date,3,2);
$day = substr($date,5,2);
That seems like a lot of lines of code, and I am believe that substr() is expensive.
Maybe I have been doing too much perl, as it seems such a neat solution to me :P
preg_match should do it...
$mydate = "20031202"; $date = array(); preg_match("/(\d{4})(\d{2})(\d{2})/", $mydate, $date); print_r($date);
substr would be much quicker though
On Tue, 2003-12-02 at 13:14, Tom wrote:
Hi.
Is there an easy, non expensive way to do the perl-equivalent of: $date=20031202; ($year, $month, $day) = ($date =~ /(\d{4})(\d{2})(\d{2})/;
I looked through the preg_* functions online, but couldn't see anything to help me. Am I stuck with substr() :P ?
Thanks.
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