function call_some_function($function,$args=NULL)
{
eval("$function($args)"); // Or something like that..
$function(); // also works I think..
}
-- 
// DvDmanDT
MSN: dvdmandt€hotmail.com
Mail: dvdmandt€telia.com
##########################
Please, if you are using windows, you may be infected by Swen. Please go
here to find out more:
http://us.mcafee.com/virusInfo/default.asp?id=helpCenter&hcName=swen
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##########################
"Ian Truelsen" <[EMAIL PROTECTED]> skrev i meddelandet
news:[EMAIL PROTECTED]
> What I want to do is to call a function from within a function, but pass
> the secondary function name through the first function. Like this:
>
> function1(function2)
>
> Then call function2 from within function1. Unfortunately, I have been
> unable to figure out the proper syntax for calling the second function.
>
> Does anyone know if this is possible and what the proper syntax would be
> for calling a function from a variable name?
>
> -- 
> Ian Truelsen
> Email: [EMAIL PROTECTED]
> AIM: ihtruelsen
> Homepage: http://www.ihtruelsen.dyndns.org

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